Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 2 - Section 2.7 - Linear Inequalities and Problem Solving - Exercise Set: 62

Answer

Maximum lengths of the other two sides are 5 and 15 in.

Work Step by Step

$12+x+3x \leq 32$ $12+4x \leq 32$ $4x \leq 20$ $x \leq 5$ Maximum value of $x$ is $5$. $x=5$ $3x=3(5)=15$ Maximum lengths of the other two sides are 5 and 15 in.
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