#### Answer

Maximum lengths of the other two sides are 5 and 15 in.

#### Work Step by Step

$12+x+3x \leq 32$
$12+4x \leq 32$
$4x \leq 20$
$x \leq 5$
Maximum value of $x$ is $5$.
$x=5$
$3x=3(5)=15$
Maximum lengths of the other two sides are 5 and 15 in.

Published by
Pearson

ISBN 10:
0321726391

ISBN 13:
978-0-32172-639-1

Maximum lengths of the other two sides are 5 and 15 in.

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