Maximum lengths of the other two sides are 5 and 15 in.
Work Step by Step
$12+x+3x \leq 32$ $12+4x \leq 32$ $4x \leq 20$ $x \leq 5$ Maximum value of $x$ is $5$. $x=5$ $3x=3(5)=15$ Maximum lengths of the other two sides are 5 and 15 in.
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