#### Answer

$z\leq0$

#### Work Step by Step

$6(2-z)\geq12$
$12-6z\geq12$
$12-6z-12\geq12-12$
$-6z\geq0$
$\dfrac{-6}{-6}z\leq\dfrac{0}{-6})$
$z\leq0$

Published by
Pearson

ISBN 10:
0321726391

ISBN 13:
978-0-32172-639-1

$z\leq0$

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