Answer
$y\gt3$
Work Step by Step
$-0.6y\lt-1.8$
$-\frac{6}{10}y\lt-\frac{18}{10}$
$\frac{10}{6}*(-\frac{6}{10}y)\lt-\frac{18}{10}*\frac{10}{6}$
$-1y\lt-3$
$y\gt3$
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