## Algebra: A Combined Approach (4th Edition)

$\frac{5}{12}$
$\frac{1}{3}$ $\times$ $\frac{4}{4}$ + f $\times$ $\frac{12}{12}$ = $\frac{3}{4}$ $\times$ $\frac{3}{3}$ $\frac{4}{12}$ + $\frac{12f}{12}$ = $\frac{9}{12}$ 4 + 12f = 9 12f = 5 f = $\frac{5}{12}$