## Algebra: A Combined Approach (4th Edition)

x = $-\frac{2}{3}$
$\frac{2}{5}x - \frac{1}{12} = -\frac{3}{5}x - \frac{3}{4}$ Add $\frac{3}{5}x$ to both sides: $\frac{5}{5}x - \frac{1}{12} = -\frac{3}{4}$ x - $\frac{1}{12} = -\frac{3}{4}$ Add $\frac{1}{12}$ to both sides: x = $-\frac{3}{4} + \frac{1}{12}$ x = $-\frac{9}{12} + \frac{1}{12}$ x = $-\frac{8}{12}$ x = $-\frac{2}{3}$ Check with substitution: $\frac{2}{5}(-\frac{2}{3}) - \frac{1}{12} = -\frac{3}{5}(-\frac{2}{3}) - \frac{3}{4}$ $-\frac{4}{15} - \frac{1}{12} = \frac{6}{15} - \frac{3}{4}$ $-\frac{1}{12} + \frac{3}{4} = \frac{6}{15} + \frac{4}{15}$ $\frac{8}{12} = \frac{10}{15}$ $\frac{2}{3} = \frac{2}{3}$