Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 13 - Test - Page 965: 2

Answer

The graph of the equation is a hyperbola with center $(0,0)$ and x-intercepts $(6,0)$ and $(-6,0)$.

Work Step by Step

The graph of an equation of the form $$\frac{x^{2}}{a^{2}}-\frac{y^{2}}{b^{2}} =1$$ is a hyperbola with center at point $(0,0)$ and x-intercepts at points $(a,0)$ and $(-a,0)$. Hence, the equation $$x^2-y^2=36$$ may be rewritten to $$\frac{x^{2}}{36}-\frac{y^{2}}{36} =1$$ by multiplying both sides of the equation by $\frac{1}{36}$. Now, we know that the center is at point $(0,0)$ and the x-intercepts are: $$x=\sqrt {36}$$ $$x= ±6$$ or $(6,0)$ and $(-6,0)$.
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