Answer
The graph of the equation is a circle with center at $(0,0)$ and $r=6$.
Work Step by Step
The center-radius form of the circle equation is in the form $$(x – h)^2 + (y – k)^2 = r^2$$ with center at $(h,k)$.
Hence, given the equation $$x^2+y^2=36$$ the center of the circle will be at $(0,0)$ and the radius will be equal to $$r=\sqrt{36}$$ $$r= 6$$
