Chapter 13 - Section 13.4 - Nonlinear Inequalities and Systems of Inequalities - Exercise Set - Page 954: 20

Please see the graph.

$y \gt x^2+x-2$ $a=1$, $b=1$, $c=-2$ Axis of symmetry is at $x=-b/2a$ $x=-b/2a$ $x=-(1)/2*1$ $x=-1/2$ $y \gt x^2+x-2$ $y \gt (-1/2)^2+(-1/2)-2$ $y \gt 1/4-1/2-2$ $y \gt -9/4$ For $x=-1/2$, as long as $y \gt -9/4$, we shade the region with that point. (Example: $y=1$, and we would shade the region with the point $(-1/2,1)$.)