Answer
Please see the graph.
Work Step by Step
$y < (x-2)^2+1$
$y=(x-2)^2+1$
$y=(x-2)(x-2)+1$
$y=x*x+x*-2+x*-2+(-2)(-2)+1$
$y=x^2-2x-2x+4+1$
$y=x^2-4x+5$
$a=1$, $b=-4$, $c=5$
Axis of symmetry is at $x=-b/2a$
$x=-b/2a$
$x=-(-4)/2*1$
$x=4/2$
$x=2$
$y < (x-2)^2+1$
$y < (2-2)^2+1$
$y < 0^2 +1$
$y< 0+1$
$y < 1$
For $x=2$, as long as $y <1$, we shade the region with that point. (Example: $y=0$, and we would shade the region with the point $(2,1)$.)
