Answer
It's a parabola
Vertex = $(-5,-2)$
Work Step by Step
$x=y^2+4y-1$
completing square and writing in vertex form $x=a(y−h)^2+k $,
$x=(y−(−2))^2-5$
The graph is a parabola and its opening to the right.
vertex : $(k;h)$
=$(−5;-2)$
the graph is shown below
