Answer
3. It's a parabola
vertex = $(-6;0)$
Work Step by Step
$y=x^2+12x+36$
writing in vertex form $y=a(x−h)^2+k$ ,
y=$(x-(-6))^2+0$
The graph is a parabola and its opening up.
vertex : $(h;k)$
=$(-6;0)$
the graph is as below
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 13 - Section 13.2 - The Ellipse and the Hyperbola - Exercise Set - Page 939: 31
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