Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Test - Page 910: 27

Answer

$5234.58

Work Step by Step

We use the formula $A=P(1+\frac{r}{n})^{nt}$ $P=4000$ $t=3$ $r=0.09$ $n=12$ $A=4000(1+\frac{0.09}{12})^{12\times3}$ $=5234.58$
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