Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Test: 17



Work Step by Step

$8^{x-1}=\frac{1}{64}$ $8^{x-1}=64^{-1}$ $8^{x-1}=(8^{2})^{-1}$ $8^{x-1}=8^{-2}$ $x-1=-2$ $x-1+1=-2+1$ $x=-1$
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