Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Section 12.7 - Common Logarithms, Natural Logarithms, and Change of Base - Exercise Set - Page 889: 5

Answer

0.6931

Work Step by Step

In order to approximate $ln(2)$, we can press the following sequence of keys on the calculator: LN then 2 then ENTER To four decimal places, $ln(2)\approx0.6931$. In other words, $e^{0.6931}\approx2$.
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