# Chapter 12 - Section 12.7 - Common Logarithms, Natural Logarithms, and Change of Base - Exercise Set - Page 889: 15

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#### Work Step by Step

Based on the definition of the common logarithm, we know that $log(x)=log_{10}x$. Furthermore, recall that $log_{b}x=y$ is equivalent to the statement $b^{y}=x$ (where $x\gt0$, $y$ is a real number, and $b\gt0$ and $b\ne1$). Therefore, $log(100)=log_{10}100=2$, because $10^{2}=100$.

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