Answer
-.68
Work Step by Step
We are given $log_{b}2=.43$ and $log_{b}3=.68$.
We know that $log_{b}\frac{x}{y}=log_{b}x-log_{b}y$ (where $x$, $y$, and $b$ are positive real numbers and $b\ne1$).
Therefore, $log_{b}\frac{3}{9}=log_{b}3-log_{b}9$.
We know that $log_{b}x^{r}=rlog_{b}x$ (where $x$ and $b$ are positive real numbers, $b\ne1$, and $r$ is a real number).
Therefore, $log_{b}3-log_{b}9=log_{b}3-log_{b}3^{2}=log_{b}3-2log_{b}3=.68-2\times.68=.68-1.36=-.68$.