#### Answer

1.29

#### Work Step by Step

We are given $log_{b}2=.43$ and $log_{b}3=.68$.
We know that $log_{b}x^{r}=rlog_{b}x$ (where $x$ and $b$ are positive real numbers, $b\ne1$, and $r$ is a real number).
Therefore, $log_{b} 8=log_{b}2^{3}=3log_{b}2=3\times.43=1.29$.