Answer
$3log_{2}y+log_{2}z$
Work Step by Step
We know that $log_{b}xy=log_{b}x+log_{b}y$ (where $x$, $y$, and $b$ are positive real numbers and $b\ne1$).
Therefore, $log_{2}y^{3}z=log_{2}y^{3}+log_{2}z$.
We know that $log_{b}x^{r}=rlog_{b}x$ (where $x$ and $b$ are positive real numbers, $b\ne1$, and $r$ is a real number).
Therefore, $log_{2}y^{3}+log_{2}z=3log_{2}y+log_{2}z$.