Answer
$log_{4}2-log_{4}(9z)$
Work Step by Step
We know that $log_{b}\frac{x}{y}=log_{b}x-log_{b}y$ (where $x$, $y$, and $b$ are positive real numbers and $b\ne1$).
Therefore, $log_{4}\frac{2}{9z}=log_{4}2-log_{4}(9z)$.
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