Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Review: 87

Answer

{$\frac{1}{2}(\frac{\log 6}{\log 3}-1)$}, {$0.3155$}

Work Step by Step

Step 1: $3^{2x+1}=6$ Step 2: $\log 3^{2x+1}=\log 6$ Step 3: $(2x+1)\log 3=\log 6$ Step 4: $(2x+1)=\frac{\log 6}{\log 3}$ Step 5: $2x=\frac{\log 6}{\log 3}-1$ Step 6: $x=\frac{1}{2}(\frac{\log 6}{\log 3}-1)\approx0.3155$ Therefore, the exact solution is {$\frac{1}{2}(\frac{\log 6}{\log 3}-1)$} whereas the four decimal approximation is {$0.3155$}.
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