Answer
$0.2231$
Work Step by Step
Typing $\ln (1.25)$ into the calculator and solving to 4 decimal places:
$\ln (1.25)\approx0.2231$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 12 - Review - Page 907: 71
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