Answer
$(h\circ g)(2)=18$
Work Step by Step
Functions involved:
$h(x)=x^3-x^2$
$g(x)=x+1$
Substitute $g(x)$ into $h(x)$:
$(h\circ g)(x)=(x+1)^3-(x+1)^2$
Substitute 2 into $(h\circ g)(x)$:
$(h\circ g)(2)=(2+1)^3-(2+1)^2$
$(h\circ g)(2)=3^3-3^2 = 27-9 = 18$
