Answer
$(f\circ g)(x)=x^2+2x-1$
Work Step by Step
Functions involved:
$f(x)=x^2-2$
$g(x)=x+1$
Substitute $g(x)$ into $f(x)$:
$(f\circ g)(x)=(x+1)^2-2$
Expand:
$(f\circ g)(x)=x^2+2x+1-2$
Simplify:
$(f\circ g)(x)=x^2+2x-1$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 12 - Review - Page 904: 5
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