Answer
$x^2+2x+4$
Work Step by Step
$x^3-8 \ \div \ x-2$
$\dfrac{x^3-8}{x-2}$
$\dfrac{x^3-2^3}{x-2}$
$\dfrac{(x-2)(x^2+2x+2^2)}{x-2}$
$x^2+2x+4$
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