Answer
$[0,6]$
Work Step by Step
$x^2-6x\leq0$
$x(x-6)\leq0$
$x=0$
$x-6=0$
$x=6$
(-infinity, $0]$
$[0,6]$
$[6$, infinity)
Let $x=-1$, $x=1$, and $x=10$
$x=-1$
$x^2-6x\leq0$
$(-1)^2-6(-1)\leq0$
$1+6\leq 0$
$7\leq 0$ (false)
$x=1$
$x^2-6x\leq0$
$1^2-6*1\leq0$
$1-6\leq 0$
$-5\leq 0$ (true)
$x=10$
$x^2-6x\leq0$
$10^2-6*10\leq0$
$100-60 \leq 0$
$40 \leq 0$ (false)
