Answer
4 seconds
Work Step by Step
$s(t) = -16t^2+80t$
Height above 96 feet
$96 \leq -16t^2+80t$
$0 \leq -16t^2+80t-96$
$0 \leq -16(t^2-5t+6)$
$0\leq -16(t-5)(t-1)$
$0 = -16(t-5)(t-1)$
$t-5 = 0$
$t=5$
$t-1=0$
$t=1$
$5-1=4$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 11 - Section 11.4 - Nonlinear Inequalities in One Variable - Exercise Set - Page 800: 64
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