Answer
The denominator in the fraction is zero when $x=3$. However, when $x=3$ (in the second function), the result is as follows:
$(x+2)(x-3)\geq 0$
$(3+2)(3-3)\geq 0$
$5*0 \geq 0$
$0 \geq 0$ (true)
Work Step by Step
Thus, when $x=3$, the first function is undefined, and the second function is true.
