Answer
$x=-1±\sqrt {13}$
Work Step by Step
$x^2+2x-12=0$
$x^2+2x+1-1-12=0$
$(x+1)^2-13=0$
$(x+1)^2=13$
$\sqrt {(x+1)^2}=\sqrt {13}$
$x+1=\sqrt {13}$
$x=-1±\sqrt {13}$
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