## Algebra: A Combined Approach (4th Edition)

Published by Pearson

# Chapter 11 - Section 11.3 - Integrated Review - Summary on Solving Quadratic Equations: 11

#### Answer

$x_{1} = -2 + \sqrt{3}i$ and $x_{2}= -2 -\sqrt{3}i$

#### Work Step by Step

Given $x^2+4x=-7 \longrightarrow x^2+4x+7=0 \\$ $a= 1, \ b=4, \ c=7$ Using the quadratic formula: $\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}$ we have: $\dfrac{-4 \pm \sqrt{4^2-4 \times 1 \times 7}}{2 \times 1} = \dfrac{-4 \pm \sqrt{16-28}}{2} = \dfrac{-4 \pm \sqrt{-12}}{2} = \dfrac{-4 \pm \sqrt{4 \times (-3)}}{2} = \dfrac{-4 \pm 2\sqrt{ (-3)}}{2} = -2 \pm \sqrt{-3} = -2 \pm \sqrt{3}i$ Therefore the solutions are $x_{1} = -2 + \sqrt{3}i$ and $x_{2}= -2 -\sqrt{3}i$

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