Answer
$y=-\dfrac{5}{2}\pm\dfrac{\sqrt{13}}{2}$
Work Step by Step
$y^{2}+5y+3=0$
Use the quadratic formula to solve this equation. The formula is $y=\dfrac{-b\pm\sqrt{b^{2}-4ac}}{2a}$. For this equation $a=1$, $b=5$ and $c=3$
Substitute:
$y=\dfrac{-5\pm\sqrt{5^{2}-4(1)(3)}}{2(1)}=\dfrac{-5\pm\sqrt{25-12}}{2}=...$
$...=\dfrac{-5\pm\sqrt{13}}{2}=-\dfrac{5}{2}\pm\dfrac{\sqrt{13}}{2}$
