Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 11 - Section 11.2 - Solving Quadratic Equations by Completing the Square - Exercise Set: 7

Answer

$x=-\dfrac{7}{2}\pm\dfrac{\sqrt{33}}{2}$

Work Step by Step

$x^{2}+7x+4=0$ Use the quadratic formula to solve this equation. The formula is $x=\dfrac{-b\pm\sqrt{b^{2}-4ac}}{2a}$. For this equation, $a=1$, $b=7$ and $c=4$ Substitute: $x=\dfrac{-7\pm\sqrt{7^{2}-4(1)(4)}}{2(1)}=\dfrac{-7\pm\sqrt{49-16}}{2}=...$ $...=\dfrac{-7\pm\sqrt{33}}{2}=-\dfrac{7}{2}\pm\dfrac{\sqrt{33}}{2}$
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