Answer
$x=-\dfrac{7}{2}\pm\dfrac{\sqrt{33}}{2}$
Work Step by Step
$x^{2}+7x+4=0$
Use the quadratic formula to solve this equation. The formula is $x=\dfrac{-b\pm\sqrt{b^{2}-4ac}}{2a}$. For this equation, $a=1$, $b=7$ and $c=4$
Substitute:
$x=\dfrac{-7\pm\sqrt{7^{2}-4(1)(4)}}{2(1)}=\dfrac{-7\pm\sqrt{49-16}}{2}=...$
$...=\dfrac{-7\pm\sqrt{33}}{2}=-\dfrac{7}{2}\pm\dfrac{\sqrt{33}}{2}$
