Answer
$\frac{1}{x-2}$
Work Step by Step
$\frac{3}{x^{2}-4}-\frac{1-x}{x^{2}-4}$
=$\frac{3-(1-x)}{x^{2}-4}$
=$\frac{3-1+x}{x^{2}-2^{2}}$
=$\frac{2+x}{(x+2)(x-2)}$
=$\frac{1}{x-2}$
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