Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Test: 32


$\sqrt 2; 5$

Work Step by Step

We find $g(0)$ and $g(23)$ by substituting $0$ and $23$ in the function of g(x): $g(0)=\sqrt {0+2}=\sqrt 2$ $g(23)=\sqrt {23+2}=\sqrt {25}=5$.
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