Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Section 10.5 - Rationalizing Numerators and Denominators of Radical Expressions - Practice: 8

Answer

$\frac{6+3\sqrt x}{4-x}$

Work Step by Step

$\frac{3}{2-\sqrt x}\times\frac{2+\sqrt x}{2+\sqrt x}$ =$\frac{3(2+\sqrt x)}{(2-\sqrt x)(2+\sqrt x)}$ =$\frac{6+3\sqrt x}{(2)^{2}-(\sqrt x)^{2}}$ =$\frac{6+3\sqrt x}{4-x}$
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