Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Section 10.5 - Rationalizing Numerators and Denominators of Radical Expressions - Practice: 6

Answer

$\frac{6\sqrt 5-3}{19}$

Work Step by Step

$\frac{3}{2\sqrt 5+1}\times\frac{2\sqrt 5-1}{2\sqrt 5-1}$ =$\frac{3\times(2\sqrt 5-1)}{(2\sqrt 5+1)(2\sqrt 5-1)}$ =$\frac{6\sqrt 5-3}{(2\sqrt 5)^{2}-(1)^{2}}$ =$\frac{6\sqrt 5-3}{4(5)-1}$ =$\frac{6\sqrt 5-3}{20-1}$ =$\frac{6\sqrt 5-3}{19}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.