Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Section 10.5 - Rationalizing Numerators and Denominators of Radical Expressions - Practice - Page 714: 6


$\frac{6\sqrt 5-3}{19}$

Work Step by Step

$\frac{3}{2\sqrt 5+1}\times\frac{2\sqrt 5-1}{2\sqrt 5-1}$ =$\frac{3\times(2\sqrt 5-1)}{(2\sqrt 5+1)(2\sqrt 5-1)}$ =$\frac{6\sqrt 5-3}{(2\sqrt 5)^{2}-(1)^{2}}$ =$\frac{6\sqrt 5-3}{4(5)-1}$ =$\frac{6\sqrt 5-3}{20-1}$ =$\frac{6\sqrt 5-3}{19}$
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