Answer
$\frac {(3y)}{\sqrt[3] {(33y^2)}}$
Work Step by Step
$\sqrt [3] {\frac {9y}{11}}$
$\sqrt [3] {\frac {(9y)(3y^2)}{11(3y^2)}}$
$\sqrt [3] {\frac {(3^2y)(3y^2)}{33y^2)}}$
$\sqrt [3] {\frac {(3^2)(y)(3)(y^2)}{33y^2)}}$
$\sqrt [3] {\frac {(3^3)(y^3)}{(33y^2)}}$
$\frac {\sqrt[3] {(3^3)(y^3)}}{\sqrt[3] {(33y^2)}}$
$\frac {(3y)}{\sqrt[3] {(33y^2)}}$
