Answer
$\frac{5(\sqrt[3] {4x})}{2x}$
Work Step by Step
$\frac{5}{\sqrt[3] {2x^2}}$
$\frac{(5)(\sqrt[3] {2x^2})(\sqrt[3] {2x^2})}{(\sqrt[3] {2x^2})(\sqrt[3] {2x^2})(\sqrt[3] {2x^2})}$
$\frac{(5)(\sqrt[3] {2x^2*2x^2})}{\sqrt[3] {2x^2*2x^2*2x^2}}$
$\frac{(5)(\sqrt[3] {2x^2*2x^2})}{\sqrt[3] {(2^3)(x^2)^3}}$
$\frac{5(\sqrt[3] {4x^4})}{2x^2}$
$\frac{5(\sqrt[3] {4x^4})}{2x^2}$
$\frac{5(\sqrt[3] {4x^4})}{2x^2}$
$\frac{5(\sqrt[3] {4x*x^3})}{2x^2}$
$\frac{5x(\sqrt[3] {4x})}{2x^2}$
$\frac{5(\sqrt[3] {4x})}{2x}$
