## Algebra: A Combined Approach (4th Edition)

$\frac{5\times\sqrt[3] (2x^{2})}{2x^{2}}$
$\frac{5}{\sqrt[3] 2x^{2}}$ - The denominator is irrational because it contains a cube root $\frac{5}{\sqrt[3] 2x^{2}}\times\frac{\sqrt[3] 2x^{2}}{\sqrt[3] 2x^{2}}\times\frac{\sqrt[3] 2x^{2}}{\sqrt[3] 2x^{2}}$ - multiply by these clever values of 1 to Rationalize the denominator $\frac{5\times\sqrt[3] (2x^{2})}{2x^{2}}$ - Is the result of the Rationalization