Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Section 10.5 - Integrated Review - Radicals and Rational Exponents - Page 721: 36


$\frac{5\times\sqrt[3] (2x^{2})}{2x^{2}}$

Work Step by Step

$\frac{5}{\sqrt[3] 2x^{2}}$ - The denominator is irrational because it contains a cube root $\frac{5}{\sqrt[3] 2x^{2}}\times\frac{\sqrt[3] 2x^{2}}{\sqrt[3] 2x^{2}}\times\frac{\sqrt[3] 2x^{2}}{\sqrt[3] 2x^{2}}$ - multiply by these clever values of 1 to Rationalize the denominator $\frac{5\times\sqrt[3] (2x^{2})}{2x^{2}}$ - Is the result of the Rationalization
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