Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Review: 148

Answer

$\frac{16}{9}$

Work Step by Step

$(\frac{27}{64})^{-\frac{2}{3}}=(\frac{3^{3}}{4^{3}})^{-\frac{2}{3}}=\frac{(3^{3})^{-\frac{2}{3}}}{(4^{3})^{-\frac{2}{3}}}=\frac{3^{-2}}{4^{-2}}=\frac{4^{2}}{3^{2}}=\frac{16}{9}$
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