#### Answer

$-x^{4}y$

#### Work Step by Step

$\sqrt[3] {-x^{12}y^{3}}$
=$(-1\times x^{12}\times y^{3})^{\frac{1}{3}}$
=$(-1)^{\frac{1}{3}}\times(x^{12})^{\frac{1}{3}}\times(y^{3})^{\frac{1}{3}}$
=$-1\times(x^{4})\times(y^{1})$
=$-x^{4}y^{1}$
=$-x^{4}y$

Published by
Pearson

ISBN 10:
0321726391

ISBN 13:
978-0-32172-639-1

$-x^{4}y$

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