## Algebra: A Combined Approach (4th Edition)

$H=\sqrt {241}$ ft
The unknown length is the hypotenuse (H). The base B is $8\sqrt 3$ ft and the perpendicular P is 7 ft. $H^{2}=(8\sqrt 3)^{2}+(7)^{2}$ $H^{2}=64(3)+49$ $H^{2}=192+49$ $H^{2}=241$ $H=\sqrt {241}$ ft