## Algebra: A Combined Approach (4th Edition)

$a+64$
$\bf{\text{Solution Outline:}}$ To multiply the given expression, $(\sqrt[3]{a}+4)(\sqrt[3]{a^2}-4\sqrt[3]{a}+16) ,$ use the concept on factoring the sum of $2$ cubes. $\bf{\text{Solution Details:}}$ Using the factoring of the sum of $2$ cubes which is given by $a^3+b^3=(a+b)(a^2-ab+b^2)$ the given expression is equivalent to \begin{array}{l}\require{cancel} (\sqrt[3]{a})^3+(4)^3 \\\\= a+64 .\end{array}