Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Appendix E - Practice: 3

Answer

$$ x = 0, y = 3$$

Work Step by Step

Using Cramer's rule: $$D =\begin{vmatrix} 4 & 1\\ 2 &-3 \end{vmatrix} = 4\times(-3) - 1\times2 = -14$$ $$D_{x} =\begin{vmatrix} 3 & 1\\ -9 &-3 \end{vmatrix} = 3\times(-3) - 1\times(-9) = 0$$ $$D_{y} =\begin{vmatrix} 4 & 3\\ 2 &-9 \end{vmatrix} = 4\times(-9) - 3\times2 = -42$$ $$ x = \frac{D_{x}}{D} = \frac{0}{-14} = 0$$ $$ y = \frac{D_{y}}{D} = \frac{-42}{-14} = 3$$
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