## Algebra: A Combined Approach (4th Edition)

$$x = 0, y = 3$$
Using Cramer's rule: $$D =\begin{vmatrix} 4 & 1\\ 2 &-3 \end{vmatrix} = 4\times(-3) - 1\times2 = -14$$ $$D_{x} =\begin{vmatrix} 3 & 1\\ -9 &-3 \end{vmatrix} = 3\times(-3) - 1\times(-9) = 0$$ $$D_{y} =\begin{vmatrix} 4 & 3\\ 2 &-9 \end{vmatrix} = 4\times(-9) - 3\times2 = -42$$ $$x = \frac{D_{x}}{D} = \frac{0}{-14} = 0$$ $$y = \frac{D_{y}}{D} = \frac{-42}{-14} = 3$$