Answer
$$ x = 0, y = 3$$
Work Step by Step
Using Cramer's rule:
$$D =\begin{vmatrix}
4 & 1\\
2 &-3
\end{vmatrix} = 4\times(-3) - 1\times2 = -14$$
$$D_{x} =\begin{vmatrix}
3 & 1\\
-9 &-3
\end{vmatrix} = 3\times(-3) - 1\times(-9) = 0$$
$$D_{y} =\begin{vmatrix}
4 & 3\\
2 &-9
\end{vmatrix} = 4\times(-9) - 3\times2 = -42$$
$$ x = \frac{D_{x}}{D} = \frac{0}{-14} = 0$$
$$ y = \frac{D_{y}}{D} = \frac{-42}{-14} = 3$$
