Answer
$(-∞,-\frac{11}{3})\cup(-3,∞)$
Work Step by Step
$|10+3x|+1>2$
$|10+3x|>1$
$10+3x1$
$3x-9$
$x-3$
$(-∞,-\frac{11}{3})\cup(-3,∞)$
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