Answer
$(-∞,\frac{2}{3})\cup(2,∞)$
Work Step by Step
$|6x-8|+3>7$
$|6x-8|>4$
$6x-84$
$6x<4$ or $6x>12$
$x2$
$(-∞,\frac{2}{3})\cup(2,∞)$
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