Answer
$[-\frac{1}{2},1]$
Work Step by Step
$6+|4x-1|\leq9$
$|4x-1|\leq3$
$-3\leq4x-1\leq3$
$-2\leq4x\leq4$
$-\frac{1}{2}\leq x\leq1$
$[-\frac{1}{2},1]$
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