#### Answer

$$d\approx 2.6$$

#### Work Step by Step

The distance $d$ between the two points $(x_{1},y_{1})$ and $(x_{2},y_{2})$ is given by
$$d=\sqrt {(x_{2}-x_{1})^{2} + (y_{2}-y_{1})^{2}}.$$
Substitute $x_{1}=0$, $y_{1}=0$, $x_{2}=4$ and $y_{2}=-3$ and round to the nearest tenth.
$$d=\sqrt {(4-0)^{2}+(-3-0)^{2}}=\sqrt {16-9}=\sqrt {7}\approx 2.6$$