Answer
$$c\approx 10.4$$
Work Step by Step
Use the Pythagorean Theorem:
$$c^{2}=a^{2}+b^{2}.$$
Substitute in $a=10$ and $b=3:$
$$c^{2}=10^{2}+3^{2}=100+9=109.$$
Take the square root of both sides:
$$\sqrt {c^{2}}=\sqrt {109}$$
$$c\approx 10.4.$$
Algebra 2 Common Core
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133186024
ISBN 13:
978-0-13318-602-4
Skills Handbook - The Pythagorean Theorem and the Distance Formula - Exercises - Page 981: 4
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