Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Entry-Level Assessment: 20

Answer

$I$

Work Step by Step

Distribute the $\sqrt 2$ to both terms: $=\sqrt{6}(\sqrt{2}) - \sqrt{2}(4) \\=\sqrt{12} -4\sqrt2$ Simplify: $=\sqrt{4\cdot 3}-4\sqrt2 \\=\sqrt4\cdot\sqrt3-4\sqrt2 \\=2\sqrt3-4\sqrt2$
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