Answer
$I$
Work Step by Step
Distribute the $\sqrt 2$ to both terms:
$=\sqrt{6}(\sqrt{2}) - \sqrt{2}(4)
\\=\sqrt{12} -4\sqrt2$
Simplify:
$=\sqrt{4\cdot 3}-4\sqrt2
\\=\sqrt4\cdot\sqrt3-4\sqrt2
\\=2\sqrt3-4\sqrt2$
Algebra 2 Common Core
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133186024
ISBN 13:
978-0-13318-602-4
Entry-Level Assessment - Page xxxvii: 20
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