## Algebra 2 Common Core

$I$
Distribute the $\sqrt 2$ to both terms: $=\sqrt{6}(\sqrt{2}) - \sqrt{2}(4) \\=\sqrt{12} -4\sqrt2$ Simplify: $=\sqrt{4\cdot 3}-4\sqrt2 \\=\sqrt4\cdot\sqrt3-4\sqrt2 \\=2\sqrt3-4\sqrt2$