## Algebra 2 Common Core

$D$
First, you want to find the slope of the lines. Because they are parallel, both lines will have the same slope. So, you're going to plug points A and B into the "point-slope formula": $(y_2 - y_1) = m(x_2 - x_1)$. So, with the coordinates of A and B, it would look like: $(4-3) = m(1-(-2)) \\1=m(1+2) \\1=m(3) \\\frac{1}{3}=m$. The slope of the lines is $\frac{1}{3}$. With this, we would need to find a point that would make our second line have the same slope. One f the points is $(1, 2)$. Checking for the $(4,3)$ as the second point gives: $(3-2) = m(4-1) \\1 = m(3) \\\frac{1}{3}=m$ The point $(4, 3)$ gives the same slope we got with our first line. Thus, point D must have the coordinates $(4, 3)$.