Answer
$ \log_3(\frac{x^4y}{z^2})$, or (A)
Work Step by Step
This applies three rules of logarithms:
$a\log(x) = \log(x^a)$
$\log(x) + \log(y) = \log(xy)$
$\log(x) - \log(y) = \log(\frac{x}{y})$
$\log_3x^4+\log_3y-\log_3z^2 = \log_3(\frac{x^4y}{z^2})$
